![]() ![]() They’re interchangeable if you want something shorter, go for -f if you want something more explicit and easily readable for someone new to this, use -force.įirst, you’ll force tag the existing tag: $ git tag -f 1.0.0 So to get around that, you’ll utilize the -f or -force flags. If you want to tag your local commit with the same tag that exists, 1.0.0, you won’t be able to: $ git tag 1.0.0 To ! 1.0.0 -> 1.0.0(already exists) error: failed to push some refs to hint: Updates were rejected because the tag already exists in the remote. You may also see other tags if they exist. When you run git tag(you could optionally put -l or -list for this), you see it as output: $ git tag 1.0.0 Having said that, let’s say that the tag 1.0.0 exists in Git. ![]() When using any sort of force commands with Git (and honestly, in general) you should be pretty confident you know what you’re doing and assuming the risks. This post won’t go into if you should do this but simply how you should. There could be various reasons why you might not want to do that (the time in between when you delete the tag and when you push the new one is time when that tag doesn’t exist at all, and that could be problematic in some cases, for instance). That’s right: one way to replace a remote tag is to actually delete the remote (and existing) one and then push your tag to the remote repository. ![]() This could arise out of you having a situation where a tag already exists remotely, but you want to update it without deleting it. This is a little specific, but let’s say you want to force push a Git tag to a remote repository. ![]()
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